Datatemplate to show an image type
WebJan 13, 2012 · One way to do it would be to create a DataTemplateSelector, and assign it to the ItemTemplateSelector property of the menu. In the code of the DataTemplateSelector, you just need to return a DataTemplate based on the enum value Share Improve this answer Follow answered Mar 14, 2010 at 16:50 Thomas Levesque 285k 67 618 753WebAn unhandled exception of type 'System.InvalidOperationException' occurred in mscorlib.dll Additional information: The calling thread must be STA, because many UI components require this. 推荐答案. 不要在视图模型中创建Image控件,尤其是当您异步加载图像时. 将视图模型更改为具有ImageSource的观察力:
Datatemplate to show an image type
Did you know?
WebAug 31, 2024 · The key to understanding Data Templates is that they are generally affiliated with the data, not the bound control. So when defining the template you specify the Type name as follows: <datatemplate datatype="{x:Type local:ClassName}"> </datatemplate>
WebMar 19, 2024 · 5. Yeah, It is possible access the view which is created using DataTemplate in run-time. Hook BindingContextChanged event for the view inside the DataTemplate from XAML. In the event call back, the view created from DataTemplate can be accessed using sender parameter. You need type cast the sender to access the view, because sender is …WebJun 9, 2024 · Here, you define a DataTemplate that shows a Rectangle in the color of the item, along with the color name and RGB values. Note When you use the x:Bind markup extension in a DataTemplate, you have to specify the DataType ( x:DataType) on the DataTemplate. XAML XAML
WebUsing C#.Net 4.5, Visual Studio 2012 Ulti, WPF. I've got some old win-forms code that i wanted to do in this new WPF app. code is the following: DataGridViewImageCell pNew = new DataGridViewImag... WebIf your ItemsSource is made up of different Types, then you can simply create HierarchicalDataTemplates and not assign an x:Key. If there is no x:Key attribute for a DataTemplate, the framework will use this DataTemplate when it comes across the type and tries to visually display it (you can read more about implicit DataTemplates …
WebC# Datagrid行详细信息中的嵌套Datagrid,c#,wpf,datagrid,C#,Wpf,Datagrid,我将一个Datagrid嵌套到主Datagrid的RowDeatils中。我正在尝试访问嵌套的Datagrid,但未成功 这是我的密码: Xaml 此代码填充名为DataGrid\u事务的主数据网格 由于无法访问,如何填充名为datagrid\u wafers\u transaction的嵌套事务 谢谢您应该向事务类添加 ...
WebAug 10, 2010 · Use a DataGridTemplateColumn to supply a DataTemplate for the column that contains an Image, and use a value converter or a data trigger to set the image source based on the value of the column. Here is an example that uses a data trigger:black line on brother scannerWebApr 11, 2024 · Hello, From this line of the code: ItemsSource=" {Binding Source= {x:Reference CarView}, Path=ItemsSource, Mode=OneWay}" , I know you want to set a BindableProperty and pass the ItemsSource. I‘m not sure what type of ItemsSource, so I set List for testing. Please refer to the following code: Consume the custom … black line on brother printerWebNov 13, 2014 · The DataContext in the DataTemplate here is in fact the Content you set for the ContentControl. Because it's already set to {Binding OverallResult}, so the Binding inside DataTemplate should be just {Binding} like this: black line on copy on hp printerWebMar 8, 2024 · 5. I have a GridViewColumn which I have bound as so: . The Binding Path = Validated returns an Enumerated value, the imageConverter takes that value and returns a …blackline on demand loginWebNov 5, 2012 · The images are not showing up in the ListBoxItems, but any other property that I bind to in the DataTemplate will show up. It may be …gant toysWebDec 23, 2015 · We can use ListView.ItemTemplate to set the DataTemplate used to display each item and put all the images into a ObservableCollection as ListView 's ItemsSource. Then in DataTemplate, we can use Bind to set the Image.Source. Following is a simple sample: In XAML, set DataTemplate with {x:Bind} to show image. gantt php open sourceWeb我有一个使用ItemsControl的Silverlight应用程序。在该ItemsControl中,我有一个定义如下的DataTemplate: XAML. 我希望在控件中显示以下属性: If OddType equal 1, than show in TextBox x:Name="OF1", if OddType equal 2, than show in TextBox x:Name="OFX", if OddType equal 3, than show in TextBox x:Name="OF3" black line on cats tooth